3.2.62 \(\int \frac {(A+B x) (b x+c x^2)^3}{\sqrt {x}} \, dx\)

Optimal. Leaf size=85 \[ \frac {2}{7} A b^3 x^{7/2}+\frac {2}{9} b^2 x^{9/2} (3 A c+b B)+\frac {2}{13} c^2 x^{13/2} (A c+3 b B)+\frac {6}{11} b c x^{11/2} (A c+b B)+\frac {2}{15} B c^3 x^{15/2} \]

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Rubi [A]  time = 0.04, antiderivative size = 85, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {765} \begin {gather*} \frac {2}{9} b^2 x^{9/2} (3 A c+b B)+\frac {2}{7} A b^3 x^{7/2}+\frac {2}{13} c^2 x^{13/2} (A c+3 b B)+\frac {6}{11} b c x^{11/2} (A c+b B)+\frac {2}{15} B c^3 x^{15/2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((A + B*x)*(b*x + c*x^2)^3)/Sqrt[x],x]

[Out]

(2*A*b^3*x^(7/2))/7 + (2*b^2*(b*B + 3*A*c)*x^(9/2))/9 + (6*b*c*(b*B + A*c)*x^(11/2))/11 + (2*c^2*(3*b*B + A*c)
*x^(13/2))/13 + (2*B*c^3*x^(15/2))/15

Rule 765

Int[((e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[Expand
Integrand[(e*x)^m*(f + g*x)*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, e, f, g, m}, x] && IntegerQ[p] && (
GtQ[p, 0] || (EqQ[a, 0] && IntegerQ[m]))

Rubi steps

\begin {align*} \int \frac {(A+B x) \left (b x+c x^2\right )^3}{\sqrt {x}} \, dx &=\int \left (A b^3 x^{5/2}+b^2 (b B+3 A c) x^{7/2}+3 b c (b B+A c) x^{9/2}+c^2 (3 b B+A c) x^{11/2}+B c^3 x^{13/2}\right ) \, dx\\ &=\frac {2}{7} A b^3 x^{7/2}+\frac {2}{9} b^2 (b B+3 A c) x^{9/2}+\frac {6}{11} b c (b B+A c) x^{11/2}+\frac {2}{13} c^2 (3 b B+A c) x^{13/2}+\frac {2}{15} B c^3 x^{15/2}\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 70, normalized size = 0.82 \begin {gather*} \frac {2 \left (B x^{7/2} (b+c x)^4-\frac {x^{7/2} \left (429 b^3+1001 b^2 c x+819 b c^2 x^2+231 c^3 x^3\right ) (7 b B-15 A c)}{3003}\right )}{15 c} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((A + B*x)*(b*x + c*x^2)^3)/Sqrt[x],x]

[Out]

(2*(B*x^(7/2)*(b + c*x)^4 - ((7*b*B - 15*A*c)*x^(7/2)*(429*b^3 + 1001*b^2*c*x + 819*b*c^2*x^2 + 231*c^3*x^3))/
3003))/(15*c)

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IntegrateAlgebraic [A]  time = 0.05, size = 97, normalized size = 1.14 \begin {gather*} \frac {2 \left (6435 A b^3 x^{7/2}+15015 A b^2 c x^{9/2}+12285 A b c^2 x^{11/2}+3465 A c^3 x^{13/2}+5005 b^3 B x^{9/2}+12285 b^2 B c x^{11/2}+10395 b B c^2 x^{13/2}+3003 B c^3 x^{15/2}\right )}{45045} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((A + B*x)*(b*x + c*x^2)^3)/Sqrt[x],x]

[Out]

(2*(6435*A*b^3*x^(7/2) + 5005*b^3*B*x^(9/2) + 15015*A*b^2*c*x^(9/2) + 12285*b^2*B*c*x^(11/2) + 12285*A*b*c^2*x
^(11/2) + 10395*b*B*c^2*x^(13/2) + 3465*A*c^3*x^(13/2) + 3003*B*c^3*x^(15/2)))/45045

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fricas [A]  time = 0.39, size = 78, normalized size = 0.92 \begin {gather*} \frac {2}{45045} \, {\left (3003 \, B c^{3} x^{7} + 6435 \, A b^{3} x^{3} + 3465 \, {\left (3 \, B b c^{2} + A c^{3}\right )} x^{6} + 12285 \, {\left (B b^{2} c + A b c^{2}\right )} x^{5} + 5005 \, {\left (B b^{3} + 3 \, A b^{2} c\right )} x^{4}\right )} \sqrt {x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(c*x^2+b*x)^3/x^(1/2),x, algorithm="fricas")

[Out]

2/45045*(3003*B*c^3*x^7 + 6435*A*b^3*x^3 + 3465*(3*B*b*c^2 + A*c^3)*x^6 + 12285*(B*b^2*c + A*b*c^2)*x^5 + 5005
*(B*b^3 + 3*A*b^2*c)*x^4)*sqrt(x)

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giac [A]  time = 0.17, size = 77, normalized size = 0.91 \begin {gather*} \frac {2}{15} \, B c^{3} x^{\frac {15}{2}} + \frac {6}{13} \, B b c^{2} x^{\frac {13}{2}} + \frac {2}{13} \, A c^{3} x^{\frac {13}{2}} + \frac {6}{11} \, B b^{2} c x^{\frac {11}{2}} + \frac {6}{11} \, A b c^{2} x^{\frac {11}{2}} + \frac {2}{9} \, B b^{3} x^{\frac {9}{2}} + \frac {2}{3} \, A b^{2} c x^{\frac {9}{2}} + \frac {2}{7} \, A b^{3} x^{\frac {7}{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(c*x^2+b*x)^3/x^(1/2),x, algorithm="giac")

[Out]

2/15*B*c^3*x^(15/2) + 6/13*B*b*c^2*x^(13/2) + 2/13*A*c^3*x^(13/2) + 6/11*B*b^2*c*x^(11/2) + 6/11*A*b*c^2*x^(11
/2) + 2/9*B*b^3*x^(9/2) + 2/3*A*b^2*c*x^(9/2) + 2/7*A*b^3*x^(7/2)

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maple [A]  time = 0.05, size = 76, normalized size = 0.89 \begin {gather*} \frac {2 \left (3003 B \,c^{3} x^{4}+3465 A \,c^{3} x^{3}+10395 B b \,c^{2} x^{3}+12285 A b \,c^{2} x^{2}+12285 B \,b^{2} c \,x^{2}+15015 A \,b^{2} c x +5005 B \,b^{3} x +6435 A \,b^{3}\right ) x^{\frac {7}{2}}}{45045} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*x+A)*(c*x^2+b*x)^3/x^(1/2),x)

[Out]

2/45045*x^(7/2)*(3003*B*c^3*x^4+3465*A*c^3*x^3+10395*B*b*c^2*x^3+12285*A*b*c^2*x^2+12285*B*b^2*c*x^2+15015*A*b
^2*c*x+5005*B*b^3*x+6435*A*b^3)

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maxima [A]  time = 0.56, size = 73, normalized size = 0.86 \begin {gather*} \frac {2}{15} \, B c^{3} x^{\frac {15}{2}} + \frac {2}{7} \, A b^{3} x^{\frac {7}{2}} + \frac {2}{13} \, {\left (3 \, B b c^{2} + A c^{3}\right )} x^{\frac {13}{2}} + \frac {6}{11} \, {\left (B b^{2} c + A b c^{2}\right )} x^{\frac {11}{2}} + \frac {2}{9} \, {\left (B b^{3} + 3 \, A b^{2} c\right )} x^{\frac {9}{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(c*x^2+b*x)^3/x^(1/2),x, algorithm="maxima")

[Out]

2/15*B*c^3*x^(15/2) + 2/7*A*b^3*x^(7/2) + 2/13*(3*B*b*c^2 + A*c^3)*x^(13/2) + 6/11*(B*b^2*c + A*b*c^2)*x^(11/2
) + 2/9*(B*b^3 + 3*A*b^2*c)*x^(9/2)

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mupad [B]  time = 0.03, size = 69, normalized size = 0.81 \begin {gather*} x^{9/2}\,\left (\frac {2\,B\,b^3}{9}+\frac {2\,A\,c\,b^2}{3}\right )+x^{13/2}\,\left (\frac {2\,A\,c^3}{13}+\frac {6\,B\,b\,c^2}{13}\right )+\frac {2\,A\,b^3\,x^{7/2}}{7}+\frac {2\,B\,c^3\,x^{15/2}}{15}+\frac {6\,b\,c\,x^{11/2}\,\left (A\,c+B\,b\right )}{11} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((b*x + c*x^2)^3*(A + B*x))/x^(1/2),x)

[Out]

x^(9/2)*((2*B*b^3)/9 + (2*A*b^2*c)/3) + x^(13/2)*((2*A*c^3)/13 + (6*B*b*c^2)/13) + (2*A*b^3*x^(7/2))/7 + (2*B*
c^3*x^(15/2))/15 + (6*b*c*x^(11/2)*(A*c + B*b))/11

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sympy [A]  time = 3.51, size = 114, normalized size = 1.34 \begin {gather*} \frac {2 A b^{3} x^{\frac {7}{2}}}{7} + \frac {2 A b^{2} c x^{\frac {9}{2}}}{3} + \frac {6 A b c^{2} x^{\frac {11}{2}}}{11} + \frac {2 A c^{3} x^{\frac {13}{2}}}{13} + \frac {2 B b^{3} x^{\frac {9}{2}}}{9} + \frac {6 B b^{2} c x^{\frac {11}{2}}}{11} + \frac {6 B b c^{2} x^{\frac {13}{2}}}{13} + \frac {2 B c^{3} x^{\frac {15}{2}}}{15} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(c*x**2+b*x)**3/x**(1/2),x)

[Out]

2*A*b**3*x**(7/2)/7 + 2*A*b**2*c*x**(9/2)/3 + 6*A*b*c**2*x**(11/2)/11 + 2*A*c**3*x**(13/2)/13 + 2*B*b**3*x**(9
/2)/9 + 6*B*b**2*c*x**(11/2)/11 + 6*B*b*c**2*x**(13/2)/13 + 2*B*c**3*x**(15/2)/15

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